Two positive point charges 15 µC and 10 µC are 30 cm apart. Calculate the work done in bringing them closer to each other by 15 cm.
Text Solution
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(4.5 J)
Sol. By energy conservation between initial and final state of the system
W + (K.E) 1 + (P.E) 1 = (K.E) 2 + (P.E) 2
W + 0 + 
= 0 + 
or, W = kq 1 q 2 
W = 9 × 10 9 × 15 × 10 –6 × 10 × 10 –6 
∴ W = 4.5 Joule
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